StrictMath.incrementExact(long) in Java

StrictMath.incrementExact(long): This method is available in java.lang.StrictMath class of Java.

Syntax:

long java.lang.StrictMath.incrementExact(long a)

This method takes one argument of type long as its parameter. This method returns the argument incremented by one,throwing an exception if the result overflows a long. The overflow only occurs for the maximum value.

Parameters: One parameter is required for this method.

a: the value to increment.

Returns: the result.

Throws:

ArithmeticException - if the result overflows a long.

Approach 1: When no exceptions.

Java

public class StrictMathincrementExactlong {
    public static void main(String[] args) {

        long a = 1911119;
        System.out.println(StrictMath.incrementExact(a));
    }
}

Output:

1911120

Approach 2: ArithmeticException 

Java

public class StrictMathincrementExactlong {
    public static void main(String[] args) {

        long a = Long.MAX_VALUE;
        System.out.println(StrictMath.incrementExact(a));
    }
}

Output:

Exception in thread "main" java.lang.ArithmeticException: long overflow
	at java.base/java.lang.Math.incrementExact(Math.java:987)
	at java.base/java.lang.StrictMath.incrementExact(StrictMath.java:864)