ArrayList.get(int) in Java

ArrayList.get(int): This method is available in java.util.ArrayList class of Java.

Syntax:

Integer java.util.ArrayList.get(int index)

This method takes one argument of type int as its parameter. This method returns the element at the specified position in this list.

Parameters: One parameter is required for this method.

index: index of the element to return.

Returns: the element at the specified position in this list.

Throws:

IndexOutOfBoundsException - if the index is out of range(index < 0 || index >= size())

Approach 1: When no exceptions

Java

import java.util.ArrayList;

public class ArrayListget {
    public static void main(String[] args) {
        ArrayList<Integer> arr = new ArrayList<>();
        arr.add(1);
        arr.add(2);
        arr.add(3);
        System.out.println(arr.get(0));

    }
}

Output:

1

Approach 2: IndexOutOfBoundsException

Java

import java.util.ArrayList;

public class ArrayListget {
    public static void main(String[] args) {
        ArrayList<Integer> arr = new ArrayList<>();
        arr.add(1);
        arr.add(2);
        arr.add(3);
        System.out.println(arr.get(4));

    }
}

Output:

Exception in thread "main" java.lang.IndexOutOfBoundsException: Index 4 out of bounds for length 3
	at java.base/jdk.internal.util.Preconditions.outOfBounds(Preconditions.java:64)
	at java.base/jdk.internal.util.Preconditions.outOfBoundsCheckIndex(Preconditions.java:70)
	at java.base/jdk.internal.util.Preconditions.checkIndex(Preconditions.java:248)
	at java.base/java.util.Objects.checkIndex(Objects.java:359)
	at java.base/java.util.ArrayList.get(ArrayList.java:427)