ArrayList.listIterator(int) in Java

ArrayList.listIterator(int): This method is available in java.util.ArrayList class of Java.

Syntax:

ListIterator<E> java.util.ArrayList.listIterator(int index)

This method takes one argument of type int as its parameter. This method returns a list iterator over the elements in this list starting at the specified position in the list.

Parameters: One parameter is required for this method.

index: index of the first element to be returned from the list iterator.

Returns: a list iterator over the elements in this list starting at the specified position in the list.

Throws:

IndexOutOfBoundsException - if the index is out of range(index < 0 || index > size())

Approach 1: When no exceptions

Java

import java.util.ArrayList;

public class ArrayListlistIterator {
    public static void main(String[] args) {
        ArrayList<Integer> arr = new ArrayList<>();
        arr.add(1);
        arr.add(2);
        arr.add(3);
        System.out.println(arr.listIterator(0));

    }
}

Output:

java.util.ArrayList$ListItr@26f0a63f

Approach 2: IndexOutOfBoundsException

Java

import java.util.ArrayList;

public class ArrayListlistIterator {
    public static void main(String[] args) {
        ArrayList<Integer> arr = new ArrayList<>();
        arr.add(1);
        arr.add(2);
        arr.add(3);
        System.out.println(arr.listIterator(4));

    }
}

Output:

Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 4, Size: 3
	at java.base/java.util.ArrayList.rangeCheckForAdd(ArrayList.java:756)
	at java.base/java.util.ArrayList.listIterator(ArrayList.java:923)