ArrayList.toArray(E[]): This method is available in java.util.ArrayList class of Java.
Syntax:
<E> E[] java.util.ArrayList.toArray(E[] a)
This method returns an array containing all of the elements in this list in proper sequence.
Parameters: One parameter is required for this method.
a: the array into which the elements of the list are to be stored, if it is big enough; otherwise, a new array of the same runtime type is allocated for this purpose.
Returns: an array containing the elements of the list.
Throws:
1. ArrayStoreException - if the runtime type of the specified array is not a super type of the runtime type of every element in this list.
2. NullPointerException - if the specified array is null
Approach 1: When no exception
Java
import java.util.ArrayList;import java.util.Arrays;public class ArrayListtoArray2 {public static void main(String[] args) {ArrayList<Integer> arr = new ArrayList<>();arr.add(1);arr.add(2);arr.add(3);Integer list2[] = new Integer[arr.size()];list2 = arr.toArray(list2);System.out.println(Arrays.toString(list2));}}
Output:
[1, 2, 3]
Approach 2: NullPointerException
Java
import java.util.ArrayList;import java.util.Arrays;public class ArrayListtoArray2 {public static void main(String[] args) {ArrayList<Integer> arr = null;Integer list2[] = new Integer[5];list2 = arr.toArray(list2);System.out.println(Arrays.toString(list2));}}
Output:
Exception in thread "main" java.lang.NullPointerException: Cannot invoke "java.util.ArrayList.toArray(Object[])" because "arr" is null
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