Number of Students Doing Homework at a Given Time

Given two integer arrays startTime and endTime and given an integer queryTime.

The ith student started doing their homework at the time startTime[i] and finished it at time endTime[i].

Return the number of students doing their homework at the time queryTime.

Example 1:

Input: startTime = [1,2,3], endTime = [3,2,7], queryTime = 4
Output: 1

Approach

Java

package com.practic.array;

public class BusyStudent {

    public static void main(String[] args) {

        int startTime[] = { 1, 2, 3 };

        int endTime[] = { 3, 2, 7 };

        int queryTime = 4;

        int totalBusy = busyStudent(startTime, endTime, queryTime);

        System.out.println(totalBusy);

    }

// method to find total busy student 

    public static int busyStudent(int[] startTime, int[] endTime, int queryTime) {

        int total = 0;

        // iterate till end of array

        for (int i = 0; i < startTime.length; i++) {

            // busy check condition here

            if (startTime[i] <= queryTime && endTime[i] >= queryTime) {

                total++;

            }

        }

        return total;

    }

}

C++

#include <bits/stdc++.h>

using namespace std;

int busyStudent(vector<int>& startTime, 

      vector<int>& endTime, int queryTime) 

{

    int n=startTime.size(),cnt=0;

    for(int i=0;i<n;i++)

       {

         if(queryTime>=startTime[i]&&queryTime<=endTime[i])

                     cnt++;

       }

     return cnt;

}

int main()

{

  vector<int> startTime ={1,2,3};

  vector<int> endTime = {3,2,7};

  int queryTime = 4;

  int busy=busyStudent(startTime,endTime,queryTime);

  cout<<busy<<"\n";

  return 0;

}