Eliminate Maximum Number of Monsters

You are playing a video game where you are defending your city from a group of n monsters. You are given a 0-indexed integer array dist of size n, where dist[i] is the initial distance in meters of the ith monster from the city.

The monsters walk toward the city at a constant speed. The speed of each monster is given to you in an integer array speed of size n, where speed[i] is the speed of the ith monster in meters per minute.

The monsters start moving at minute 0. You have a weapon that you can choose to use at the start of every minute, including minute 0. You cannot use the weapon in the middle of a minute. The weapon can eliminate any monster that is still alive. You lose when any monster reaches your city. If a monster reaches the city exactly at the start of a minute, it counts as a loss, and the game ends before you can use your weapon in that minute.

Return the maximum number of monsters that you can eliminate before you lose, or n if you can eliminate all the monsters before they reach the city.

Example 1:

Input: dist = [1,3,4], speed = [1,1,1]
Output: 3
Explanation:
At the start of minute 0, the distances of the monsters are [1,3,4], you eliminate the first monster.
At the start of minute 1, the distances of the monsters are [X,2,3], you don't do anything.
At the start of minute 2, the distances of the monsters are [X,1,2], you eliminate the second monster.
At the start of minute 3, the distances of the monsters are [X,X,1], you eliminate the third monster.
All 3 monsters can be eliminated.

Example 2:

Input: dist = [1,1,2,3], speed = [1,1,1,1]
Output: 1
Explanation:
At the start of minute 0, the distances of the monsters are [1,1,2,3], you eliminate the first monster.
At the start of minute 1, the distances of the monsters are [X,0,1,2], so you lose.
You can only eliminate 1 monster.

Example 3:

Input: dist = [3,2,4], speed = [5,3,2]
Output: 1
Explanation:
At the start of minute 0, the distances of the monsters are [3,2,4], you eliminate the first monster.
At the start of minute 1, the distances of the monsters are [X,0,2], so you lose.
You can only eliminate 1 monster.

Approach

C++

#include <bits/stdc++.h>
using namespace std;

int eliminateMaximum(vector<int&distvector<int&speed)
{
    for (int i = 0i < dist.size(); i++)
    {
        dist[i] = (dist[i] - 1) / speed[i];
    }
    sort(dist.begin(), dist.end());

    for (int i = 0i < dist.size(); i++)
    {
        if (i > dist[i])
            return i;
    }
    return dist.size();
}

int main()
{
    vector<intdist = {134}, speed = {111};

    cout << eliminateMaximum(distspeed<< "\n";

    return 0;
}


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