Arrays.equals(Object[], int, int, Object[], int, int): This method is available in java.util.Arrays class of Java.
Syntax:
boolean java.util.Arrays.equals(Object[] a, int aFromIndex, int aToIndex, Object[] b, int bFromIndex, int bToIndex)
This method takes six arguments two of type Object array and the rest four are of type int as its parameters. This method returns true if the two specified arrays of Objects, over the specified ranges, are equal to one another.
Parameters: Six parameters are required for this method.
a: the first array to be tested for equality.
aFromIndex: the index (inclusive) of the first element in the first array to be tested.
aToIndex: the index (exclusive) of the last element in the first array to be tested.
b: the second array to be tested for equality.
bFromIndex: the index (inclusive) of the first element in the second array to be tested.
bToIndex: the index (exclusive) of the last element in the second array to be tested.
Returns: true if the two arrays, over the specified ranges, are equal.
Throws:
1. IllegalArgumentException - if aFromIndex > aToIndex or if bFromIndex > bToIndex.
2. ArrayIndexOutOfBoundsException - if aFromIndex < 0 or aToIndex > a.length or if bFromIndex < 0 or bToIndex > b.length.
3. NullPointerException - if either array is null.
Approach 1: When no exceptions
Java
import java.util.Arrays;public class Arraysequalsobjectrange {public static void main(String[] args) {Object a[] = { 1, 1, 0, 1, 1, 0 };int aFromIndex = 2, aToIndex = 4;Object b[] = { 0, 0, 1, 1, 1 };int bFromIndex = 1, bToIndex = 3;System.out.println(Arrays.equals(a, aFromIndex,aToIndex, b, bFromIndex, bToIndex));}}
Output:
true
Approach 2: IllegalArgumentException
Java
import java.util.Arrays;public class Arraysequalsobjectrange {public static void main(String[] args) {Object a[] = { 1, 1, 0, 1, 1, 0 };int aFromIndex = 5, aToIndex = 4;Object b[] = { 0, 0, 1, 1, 1 };int bFromIndex = 1, bToIndex = 3;System.out.println(Arrays.equals(a, aFromIndex,aToIndex, b, bFromIndex, bToIndex));}}
Output:
Exception in thread "main" java.lang.IllegalArgumentException: fromIndex(5) > toIndex(4) at java.base/java.util.Arrays.rangeCheck(Arrays.java:718) at java.base/java.util.Arrays.equals(Arrays.java:3022)
Approach 3: ArrayIndexOutOfBoundsException
Java
import java.util.Arrays;public class Arraysequalsobjectrange {public static void main(String[] args) {Object a[] = { 1, 1, 0, 1, 1, 0 };int aFromIndex = -1, aToIndex = 4;Object b[] = { 0, 0, 1, 1, 1 };int bFromIndex = 1, bToIndex = 3;System.out.println(Arrays.equals(a, aFromIndex,aToIndex, b, bFromIndex, bToIndex));}}
Output:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Array index out of range: -1 at java.base/java.util.Arrays.rangeCheck(Arrays.java:722) at java.base/java.util.Arrays.equals(Arrays.java:3022)
Approach 4: NullPointerException
Java
import java.util.Arrays;public class Arraysequalsobjectrange {public static void main(String[] args) {Object a[] = null;int aFromIndex = 2, aToIndex = 4;Object b[] = { 0, 0, 1, 1, 1 };int bFromIndex = 1, bToIndex = 3;System.out.println(Arrays.equals(a, aFromIndex,aToIndex, b, bFromIndex, bToIndex));}}
Output:
Exception in thread "main" java.lang.NullPointerException: Cannot read the array length because "a" is null at java.base/java.util.Arrays.equals(Arrays.java:3022)
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