BufferedInputStream skip(long) in Java

skip(long): This method is available in the java.io.BufferedInputStream class of Java.

Syntax:

long java.io.BufferedInputStream.skip(long n) throws IOException

This method takes one argument. This method tries to skip the n number of bytes.

Parameters: One parameter is required for this method.

n: the number of bytes to be skipped.

Returns: the actual number of bytes skipped.

Throws:

IOException - if this input stream has been closed by invoking its close() method, in.skip(n) throws an IOException or an I/O error occurs.

Approach 1: When no exception

Java

import java.io.BufferedInputStream;
import java.io.IOException;
import java.io.InputStream;

public class BufferedInputStreamskip {
    public static void main(String[] args) throws IOException {

        InputStream inputStream = InputStream.nullInputStream();
        BufferedInputStream bufferedInputStream = 
                    new BufferedInputStream(inputStream);

        long n = 2;

        System.out.println(bufferedInputStream.skip(n));
    }
}

Output:

0

Approach 2: IOException 

Java

import java.io.BufferedInputStream;
import java.io.IOException;
import java.io.InputStream;

public class BufferedInputStreamskip {
    public static void main(String[] args) throws IOException {

        InputStream inputStream = InputStream.nullInputStream();
        BufferedInputStream bufferedInputStream = 
            new BufferedInputStream(inputStream);

        long n = 2;

        bufferedInputStream.close();
        System.out.println(bufferedInputStream.skip(n));
    }
}

Output:

Exception in thread "main" java.io.IOException: Stream closed
	at java.base/java.io.BufferedInputStream.getBufIfOpen(BufferedInputStream.java:168)
	at java.base/java.io.BufferedInputStream.skip(BufferedInputStream.java:366)