The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially positioned in the top-left room and must fight his way through the dungeon to rescue the princess.
The knight has an initial health point represented by a positive integer. If at any point his health point drops to 0 or below, he dies immediately.
Some of the rooms are guarded by demons, so the knight loses health (negative integers) upon entering these rooms; other rooms are either empty (0's) or contain magic orbs that increase the knight's health (positive integers).
In order to reach the princess as quickly as possible, the knight decides to move only rightward or downward in each step.
The knight has an initial health point represented by a positive integer. If at any point his health point drops to 0 or below, he dies immediately.
Some of the rooms are guarded by demons, so the knight loses health (negative integers) upon entering these rooms; other rooms are either empty (0's) or contain magic orbs that increase the knight's health (positive integers).
In order to reach the princess as quickly as possible, the knight decides to move only rightward or downward in each step.
Find the knight's minimum initial health so that he is able to rescue the princess.
Example:
Input: {{-2,-3,3},{-5,-10,1},{10,30,-5}}
Output: 7
Approach
Java
public class DungeonGame {public static void main(String[] args) {int[][] dungeon = { { -2, -3, 3 }, { -5, -10, 1 }, { 10, 30, -5 } };System.out.println(calculateMinimumHP(dungeon));}static int calculateMinimumHP(int[][] dungeon) {int m = dungeon.length;int n = dungeon[0].length;for (int i = m - 1; i >= 0; i--) {for (int j = n - 1; j >= 0; j--) {// if we reach at end of the gridif (i == m - 1 && j == n - 1) {// if value is positiveif (dungeon[i][j] > 0)dungeon[i][j] = 1;// if value is negativeelsedungeon[i][j] = -1 * dungeon[i][j] + 1;}// if we are at last rowelse if (i == m - 1) {// if value is positiveif (dungeon[i][j] > 0)dungeon[i][j] = Math.max(1, dungeon[i][j + 1] - dungeon[i][j]);// if value is negativeelsedungeon[i][j] = -1 * dungeon[i][j] + dungeon[i][j + 1];}// if we are at last columnelse if (j == n - 1) {// if value is positiveif (dungeon[i][j] > 0)dungeon[i][j] = Math.max(1, dungeon[i + 1][j] - dungeon[i][j]);// if value is negativeelsedungeon[i][j] = -1 * dungeon[i][j] + dungeon[i + 1][j];}// if value at the current cell is positiveelse if (dungeon[i][j] > 0) {int x = Math.max(1, dungeon[i + 1][j] - dungeon[i][j]);int y = Math.max(1, dungeon[i][j + 1] - dungeon[i][j]);// update the current cell valuedungeon[i][j] = Math.min(x, y);}// else the value at current cell is negativeelsedungeon[i][j] = -1 * dungeon[i][j] + Math.min(dungeon[i][j + 1], dungeon[i + 1][j]);}}return dungeon[0][0];}}
C++
#include <bits/stdc++.h>using namespace std;int calculateMinimumHP(vector<vector<int>>& dungeon){int m=dungeon.size();int n=dungeon[0].size();for(int i=m-1;i>=0;i--){for(int j=n-1;j>=0;j--){//if we reach at end of the gridif(i==m-1&&j==n-1){//if value is positiveif(dungeon[i][j]>0)dungeon[i][j]=1;//if value is negativeelsedungeon[i][j]=-1*dungeon[i][j]+1;}//if we are at last rowelse if(i==m-1){//if value is positiveif(dungeon[i][j]>0)dungeon[i][j]=max(1,dungeon[i][j+1]-dungeon[i][j]);//if value is negativeelsedungeon[i][j]=-1*dungeon[i][j]+dungeon[i][j+1];}//if we are at last columnelse if(j==n-1){//if value is positiveif(dungeon[i][j]>0)dungeon[i][j]=max(1,dungeon[i+1][j]-dungeon[i][j]);//if value is negativeelsedungeon[i][j]=-1*dungeon[i][j]+dungeon[i+1][j];}//if value at the current cell is positiveelse if(dungeon[i][j]>0){int x=max(1,dungeon[i+1][j]-dungeon[i][j]);int y=max(1,dungeon[i][j+1]-dungeon[i][j]);//update the current cell valuedungeon[i][j]=min(x,y);}//else the value at current cell is negativeelsedungeon[i][j]=-1*dungeon[i][j]+min(dungeon[i][j+1],dungeon[i+1][j]);}}return dungeon[0][0];}int main(){vector<vector<int>> dungeon={{-2,-3,3},{-5,-10,1},{10,30,-5}};cout<<calculateMinimumHP(dungeon);return 0;}
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