You are given an array A. You can decrement any element of the array by 1. This operation can be repeated any number of times. A number is said to be missing if it is the smallest positive number which is a multiple of 2 that is not present in array A. You have to find the maximum missing number after all possible decrements of the elements.
Example:
Input: n = 6, a = [1 3 3 3 6 7]
Output: 8
Approach
C++
#include <bits/stdc++.h>using namespace std;long long missingNumbers(long long n, long long a[]){sort(a, a + n);long long res = 2;for (long long i = 0; i < n; i++){if (a[i] >= res)res += 2;}return res;}int main(){long long n = 6;long long a[n] = {1, 3, 3, 3, 6, 7};cout << missingNumbers(n, a) << "\n";return 0;}
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