Being Code Expert: Unsafe elements in a matrix

You have a matrix $S$ consisting of $N$ rows and $M$ columns. Let $u$ be the maximum element of the matrix and $v$ be the smallest element of the matrix. If any element whose value is equal to $u$ or $v$ are called unsafe elements and they disfigure the complete row and column of the matrix. More formally, if any element is equal to $u$ or $v$ and contains cell number $(x, y)$ , that is, $S [x] [y] = u$ or $S [x] [y] = v$ are unsafe so that they also disfigure all the cells that have row $x$ or column $y$ and also are unsafe.

Your task is to find the number of safe elements.

Example:

Input:
3 3
8 8 3
6 2 4
12 1 2
Output:
2

Approach

Java

package com.java;

import java.util.HashSet;

public class UnsafeElemINMatrix {

    public static void main(String[] args) {
        int r = 3;
        int c = 3;

        int min = 999999999;
        int max = 0;
        int[][] arr = { { 8, 8, 3 }, { 6, 2, 4 }, { 12, 1, 2 } };
        for (int i = 0; i < r; i++) {
            for (int j = 0; j < c; j++) {
                int val = arr[i][j];
                arr[i][j] = val;
                if (val > max) {
                    max = val;
                }
                if (val < min) {
                    min = val;
                }
            }
        }
        int rows = 0;
        HashSet<Integer> columns = new HashSet<Integer>();
        for (int i = 0; i < r; i++) {
            boolean pass = false;
            for (int j = 0; j < c; j++) {
                int val = arr[i][j];
                if (val == max || val == min) {
                    if (!columns.contains(val)) {
                        columns.add(val);
                    }

                    pass = true;
                }
            }
            if (pass) {
                rows++;
            }
        }

        System.out.println((r - rows) * (c - columns.size()));
    }

}