Designer PDF Viewer

When a contiguous block of text is selected in a PDF viewer, the selection is highlighted with a blue rectangle. In this PDF viewer, each word is highlighted independently

There is a list of 26 character heights aligned by index to their letters. For example, 'a' is at index 0 and 'z' is at index 25. There will also be a string. Using the letter heights given, determine the area of the rectangle highlight in mm^2 assuming all letters are 1mm wide.

Example:

Input:  h={1, 3, 1, 3, 1, 4, 1, 3, 2, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5}, word="abc"
Output: 9

Approach

Java


public class DesignerPDFViewer {
    public static void main(String[] args) {
        int[] h = { 13131413255555,
             555555555555 };
        String word = "abc";
        System.out.println(designerPdfViewer(h, word));
    }

    private static int designerPdfViewer(int[] hString word) {

        int m = word.length();
        int c[] = new int[m];
        int k = 0;
        for (int j = 0; j < m; j++) {
            int x = 97;
            while (word.charAt(j) != x && x <= 122) {
                x++;
            }
            c[k] = h[x - 97];
            k++;
        }
        int large = c[0];
        for (int i = 1; i < m; i++) {
            if (c[i] > large)
                large = c[i];
        }
        return large * m;
    }
}


C++

#include <bits/stdc++.h>
using namespace std;

int designerPdfViewer(vector<inthstring word)
{
    int m = word.size();
    int c[m];
    int k = 0;
    for (int j = 0j < mj++)
    {
        int x = 97;
        while (word[j] != x && x <= 122)
        {
            x++;
        }
        c[k] = h[x - 97];
        k++;
    }
    int large = c[0];
    for (int i = 1i < mi++)
    {
        if (c[i] > large)
            large = c[i];
    }
    return large * m;
}

int main()
{

    vector<inth = {131314132,
  555555555555
55555};
    string word = "abc";
    cout << designerPdfViewer(hword);
    return 0;
}


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