A perfect number is a positive integer that is equal to the sum of its positive divisors, excluding the number itself. A divisor of an integer x
is an integer that can divide x
evenly.
Given an integer n
, return true
if n
is a perfect number, otherwise return false
.
Example:
Input: num = 28
Output: true
Explanation: 28 = 1 + 2 + 4 + 7 + 14
1, 2, 4, 7, and 14 are all divisors of 28.
Approach:
C++
#include <bits/stdc++.h>using namespace std;int perfectNumber(int n){int sum = 0;for (int i = 1; i <= sqrt(n); i++){if (n % i == 0){if (n / i == i)sum += n / i;elsesum += n / i + i;}}return sum;}bool checkPerfectNumber(int num){if (num == 0)return false;int res = perfectNumber(num);if (res - num == num)return true;return false;}int main(){int n = 28;if (checkPerfectNumber(n)){cout << "true";}else{cout << "false";}return 0;}
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